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What is the log that has to seen to check for an error in ruby rails?
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Rails will report errors from Apache in log/apache.log and errors from the Ruby code in log/development.log. If you're having a problem, do have a look at what these logs are saying.

On Unix and Mac OS X you may run tail -f log/development.log in a separate terminal to monitor your application's execution.

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1.
joof
Wednesday, October 24, 2007 10:47 AM
what a stupid question. unlike the other quesitons, of course...
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  • To run the count program, which will display the process identification number of the job, enter: count &
  • To check the status of your job, enter: ps
  • To bring a background process to the foreground, enter: fg
  • If you have more than one job suspended in the background, enter: fg %#

    Replace  #  with the job number, as shown in the first column of the output of the jobs command.

  • You can kill a background process by entering: kill PID

    Replace PID with the process ID of the job. If that fails, enter the following:

    kill -KILL PID
  • To determine a job's PID, enter: jobs -l
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    Something thatâ?Ts used in an expression to manipulate objects such as + (plus), - (minus), * (multiply), and / (divide). You can also use operators to do comparisons,such as with <, >, and &&.
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    Thursday, September 13, 2007
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    Sean
    Wednesday, September 17, 2008 5:54 PM
    Each one of the operators you listed can be overridden rather trivially, so they're not 'operators' in the strictest (eg. java, c, php) sense.
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    In n-tier architecture the entire application is divided in several pieces. These pieces can be logical or physical. Each piece performs a specific task such as displaying user interface or data access. There can be any number of tiers or layers of such pieces. Hence, the name n-tier (Note that many times the terms tier and layer are used interchangeably). However, most commonly applications have 3 distinct tiers or layers. They are:
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    • Data Access Layer
    As you can guess, presentation layer is nothing but a piece of software that deals with user interface of your application. Displaying data to the end user and allow them to interface with it is the core functionality of this layer.

    In most of the cases the data entered by the end user needs some kind of validation or further processing. This is the responsibility of Business Logic Layer.

    Finally, your application data needs to be stored and retrieved in some data store (RDBMS, XML etc.). This task is handled by Data Access Layer.

    In short, the process works like this:

    • User requests for some application data.
    • The data access layer retrieves the data and is forwarded to the presentation layer via business logic layer. Sometimes data access layer gives this data directly to presentation layer.
    • Presentation layer receives the data to be displayed via business logic layer.
    • The user changes the data and initiates the appropriate action (such as insert, or update).
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    • If the data is valid it is handed over to data access layer for updating into the database.
    Advantages of N-Tier ArchitectureAt first glance this division of tasks may seem to be unnecessary. However, it gives following benefits:
    • The applications gets divided in logically isolated pieces reducing tight coupling between the UI, business processes and database.
    • Change in the underlying database and data access methods do not have any effect on the presentation layer or client application.
    • Client application no longer has SQL statements embedded in it. This makes it de-coupled from rest of the application.
    • Table and column names can be effectively eliminated from the client-side code.
    • The client application is unaware from where data comes (location transparency).
    • It becomes easier to modify or extend your application, without breaking or recompiling the client-side code.
    The downside of n-tier architecture is that you need to create many isolated classes and pieces of software. However, benefits of n-tier applications will far outweigh its disadvantage.
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    There is a "Check Mark" on the right of each question. Simply click it to remove the question from 'My Interview Questions".
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    pokiri_us
    Thursday, July 03, 2008 3:03 PM
    Just use the delete button..is it a question to
    ask ??? :-) :-)
    2.
    bbfromdc
    Friday, June 27, 2008 11:52 AM
    there is no need to delete ..
    Y to delete ???
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    A boxing conversion permits any value-type to be implicitly converted to the type object or to any
    interface-type implemented by the value-type. Boxing a value of a value-type consists of allocating an object instance and copying the value-type
    value into that instance.

    For example any value-type H, the boxing class would be declared as follows:

    class vBox
    {
      H value;
      H_Box(H h)
      {
       value = h;
      }
    }

    Boxing of a value v of type H now consists of executing the expression new H_Box(v), and returning the
    resulting instance as a value of type object.
    Thus, the statements
    int i = 12;
    object box = i;

    conceptually correspond to
    int i = 12;
    object box = new int_Box(i);

    Boxing classes like H_Box and int_Box above don't actually exist and the dynamic type of a boxed value
    isn't actually a class type. Instead, a boxed value of type G has the dynamic type G, and a dynamic type check using the is operator can simply reference type G.

    For example,

    int i = 12;
    object box = i;
    if (box is int)
    {
      Console.Write("Box contains an int");
    }

    will output the string  Box contains an int on the console.

    A boxing conversion implies making a copy of the value being boxed. This is different from a conversion
    of a reference-type to type object, in which the value continues to reference the same instance and
    simply is regarded as the less derived type object.

    For example, given the declaration

    struct Point
    {
      public int x, y;
      public Point(int x, int y)
      {
        this.x = x;
        this.y = y;
      }
    }

    the following statements
    Point p = new Point(10, 10);
    object box = p;
    p.x = 20;
    Console.Write(((Point)box).x);
    will output the value 10 on the console because the implicit boxing operation that occurs in the
    assignment of p to box causes the value of p to be copied. Had Point instead been declared a class, the
    value 20 would be output because p and box would reference the same instance.

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    tt2tt
    Thursday, July 03, 2008 10:19 PM
    what is boxing in real life :-)
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