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#error is the preprocessor directive which produces compile time error messages. These directives are most useful for detecting programmer inconsistencies and violation of constraints during preprocessing.

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Wednesday, November 07, 2007
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Francesco8106
Wednesday, August 26, 2009 8:56 AM
Al momento non sono ancora in grado d'espletare alcun giudizio al riguardo.
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A boxing conversion permits any value-type to be implicitly converted to the type object or to any
interface-type implemented by the value-type. Boxing a value of a value-type consists of allocating an object instance and copying the value-type
value into that instance.

For example any value-type H, the boxing class would be declared as follows:

class vBox
{
  H value;
  H_Box(H h)
  {
   value = h;
  }
}

Boxing of a value v of type H now consists of executing the expression new H_Box(v), and returning the
resulting instance as a value of type object.
Thus, the statements
int i = 12;
object box = i;

conceptually correspond to
int i = 12;
object box = new int_Box(i);

Boxing classes like H_Box and int_Box above don't actually exist and the dynamic type of a boxed value
isn't actually a class type. Instead, a boxed value of type G has the dynamic type G, and a dynamic type check using the is operator can simply reference type G.

For example,

int i = 12;
object box = i;
if (box is int)
{
  Console.Write("Box contains an int");
}

will output the string  Box contains an int on the console.

A boxing conversion implies making a copy of the value being boxed. This is different from a conversion
of a reference-type to type object, in which the value continues to reference the same instance and
simply is regarded as the less derived type object.

For example, given the declaration

struct Point
{
  public int x, y;
  public Point(int x, int y)
  {
    this.x = x;
    this.y = y;
  }
}

the following statements
Point p = new Point(10, 10);
object box = p;
p.x = 20;
Console.Write(((Point)box).x);
will output the value 10 on the console because the implicit boxing operation that occurs in the
assignment of p to box causes the value of p to be copied. Had Point instead been declared a class, the
value 20 would be output because p and box would reference the same instance.

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Tuesday, June 10, 2008
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tt2tt
Thursday, July 03, 2008 10:19 PM
what is boxing in real life :-)
35000
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Wednesday, May 14, 2008
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Tuesday, May 13, 2008
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Tuesday, May 13, 2008
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Monday, May 12, 2008
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Monday, May 12, 2008
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The class System has a variable out that represents the standard output, and the variable err that represents the standard error device. By default, they both point at the system console. This how the standard output could be re-directed:Stream st = new Stream(new FileOutputStream("output.txt")); System.setErr(st); System.setOut(st);
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Saturday, May 10, 2008
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An abstract class may contain code in method bodies, which is not allowed in an interface. With abstract classes, you have to inherit your class from it and Java does not allow multiple inheritance. On the other hand, you can implement multiple interfaces in your class.
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Saturday, May 10, 2008
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Synchronized blocks place locks for shorter periods than synchronized methods.
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